Solving inequality g (x) ≥ f (x) - / X-1/

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• 1. To solve an inequality with absolute values on both sides |Is there any difference between X ^ 2-5x + 4 / x ^ 2-4 | 1 and x ^ 2-5x + 4 / | x ^ 2-4 | 1
• 2. Let, α, β ∈ (0, π / 2) and sin β = sin α cos (α + β), use the inequality a + B ≥ 2 √ AB (a > 0, b > 0) to find the maximum value of Tan β
• 3. Let α and β belong to [- π / 2, π / 2] and satisfy the inequality sin α cos β + sin β cos α = 1, then the value range of sin α + sin β is obtained
• 4. If α∈ (π 4, π 2), then the following inequality holds () A. sinα＞cosα＞tanαB. sinα＞tanα＞cosαC. tanα＞sinα＞cosαD. cosα＞tanα＞sinα
• 5. The results show that: (1) sin α > 1 / 2; (2) cos α > 1 / 2; (3) Tan α > 1 / 2
• 6. Square of sin β + square of cos β + Tan β cot β
• 7. (Tan x + cot x) cos square x=
• 8. How does cos square become 1 / 1 + Tan square theta
• 9. It is proved that 1 + sin2 θ + Cos2 θ / 1 + sin θ - Cos2 θ = Tan θ
• 10. When x ∈ (0, π), the minimum value of F (x) = 1 + cos2x + 3sin2xsinx is () A. 22B. 3C. 23D. 4
• 11. If f (x) = 2 Λ x, G (x) = 4 Λ x, then the solution set of the inequality f (g (x)) < g (f (x))?
• 12. If the solution set of the inequality f (x) ≥ 0 is [2,4], and the solution set of the inequality g (x) ≥ 0 is ±, then the solution set of the inequality f (x) g (x) > 0 is______ ．
• 13. Given that f (x) = a ^ x, G (x) = a ^ (x ^ 2-x-3) (a > 0, a ≠ 1), try to find the solution set of the inequality f (x) ≤ g (x)
• 14. Let the solution set of inequality f (x) ≥ 0 be [1,2], and the solution set of inequality g (x) ≥ 0 be an empty set Let the solution set of inequality f (x) ≥ 0 be [1,2], and the solution set of inequality g (x) ≥ 0 be an empty set, then if the solution set of inequality f (x) / g (x) > 0 is complete, there is another answer
• 15. Inequality 4x-5
• 16. How many square meters is 140 square decimeters equal to
• 17. How many square meters is 30 square decimeters? How many hours is 24 minutes? How many kilograms is 750 meters? How many kilograms is 450 grams
• 18. 70 square decimeters equals () square meters fill in the simplest score
• 19. It is known that a, B and C are all integers. When the value of the algebraic formula 7a + 2B + 3C can be divisible by 13, can the value of the algebraic formula 5A + 7b-22c be divisible by 13? Why?
• 20. 3A + 2B + C = 5,2a + b-3c = 1,3a + b-7c = m, a, B and C are expressed by algebraic expressions containing m respectively