Why 2Ab + 2BC + 2Ac = - (A & # 178; + B & # 178; + C & # 178;) = - 100 why a & # 178; + B & # 178; + C & # 178; + 2Ab + 2B + 2BC = 0 | Math enthusiast | Mathematical art

Why 2Ab + 2BC + 2Ac = - (A & # 178; + B & # 178; + C & # 178;) = - 100 why a & # 178; + B & # 178; + C & # 178; + 2Ab + 2B + 2BC = 0

(a + B + B + B + C) this is the 178; (; (; (a + B + b) + C] this is the 178; = [(a + B + b) + C; (; (; (a + b); (a + b); (a + b) ; (; (a + b) ; (; (; (a + b) ; (; (; (a + b) ; (; (a + B + b) + C] this is the 178; (; (; (a + b) \; (; (; (a + b) \\\; (; (; (; (a + b) ; (; (b) \\\\; (; (; (; (; (; (a + b) \\\\\\\\\\\\\ + C & #178;)

RELATED INFORMATIONS

1. Known: a = B & # 178; + C & # 178; - A & # 178; / 2BC, B = A & # 178; + C & # 178; - B & # 178; / 2Ac, C = A & # 178; + B & # 178; - C & # 178; / 2Ab And a + B = C, find the value of a to the power of 2013 + B to the power of 2013 + C to the power of 2013
2. Divide the quarter circle into a triangle and a geometric figure, the triangle is 10cm & # 178;, ask the area of the geometric figure
3. a. BC is three positive integers, B & # 178; = 2Ac + 1, a square with B as the side and a rectangle with a and C as the length and width respectively. What is the area of the figure
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