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The goods can be transported 6 / 5 in 6 days by ab. if the goods are transported alone, it takes the same time for a to transport 3 / 1 and B to transport 2 / 1
Note: the left side is numerator, the right side is denominator AB two car efficiency sum: (5 / 6) / 6 = 5 / 36 efficiency ratio: A: B = 1 / 3:1 / 2 = 2:3 (in this case, the efficiency of a is 2, the efficiency of B is 3), then each is: (5 / 36) * (1 / 5) = 1 / 36a efficiency: 1 / 36 * 2 = 1 / 18B efficiency: 1 / 36 * 3 = 1 / 12a single
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