Let x > 0, Y > 0 and X + 2Y = 1, find the minimum value of 1x + 1y___ ．

According to the meaning of the question, if x + 2Y = 1, then 1x + 1y = (x + 2Y) · (1x + 1y) = 3 + 2yx + XY ≥ 3 + 22yx × xy = 3 + 22, so the answer is 3 + 22

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