As shown in the figure, in the triangle ABC, ∠ a = 40 °, CE is the bisector of the outer angle of ∠ ABC, and CE ‖ AB, calculate the degree of ∠ B and ∠ ACB
Er, are you sure the title is OK? If the title is "CE is the outer bisector of ∠ ACB":
∵∠A=40°
∠ ECH (H is AC extension line) = 40 °
∴∠BCE=40°
∴∠ACB=100°
∴∠B=40°
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