Let the two focal points of the hyperbola be f 1. F 2. If | pf 2 | = 2 | f 1F 2 |, then the eccentricity of the hyperbola is zero

Let the two focal points of the hyperbola be f 1. F 2. If | pf 2 | = 2 | f 1F 2 |, then the eccentricity of the hyperbola is zero

Because F1F2 is 2c, PF2 is C. because the angle pf2f1 is 90 degrees, Pf1 is root 5 C, because a = (root 5 C-C) / 2
So the centrifugation is a / C = (radical 5 - 1) / 2