When k is a value, the function f (x) has continuity in its domain f（x）=sinx/x x=0

lim(sinx/x)=1 (x→0)
Therefore, for the formula 3x ^ 2-2x + K, when x = 0, the value of the formula must be LIM (SiNx / x) = 1 for the original function to be continuous
The solution is k = 1

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