The solution of the equation 3x + YK + 2,2x-y = 5 is x > 0, y < 0, and the value range of K is obtained 3x+y=k+2

Solve the equations 3x + YK = 2,
2x-y=5
X = (5K + 2) / (3 + 2K)
y=-11/(3+2k)
From x > 0, Y0 and 3 + 2K > 0,
(2)5k+2

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