Let the integral part of 1 (3 - √ 5) be a and the decimal part be B. find A-1 / b | Math enthusiast | Mathematical art

Let the integral part of 1 (3 - √ 5) be a and the decimal part be B. find A-1 / b

1/(3-√5)=(3+√5)/4≈1.3
So a = 1, B = (3 + √ 5) / 4-1 = (√ 5-1) / 4
So A-1 / b = 1-4 / (√ 5-1) = 1 - (√ 5 + 1) = - √ 5
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