If a / b = C / D = E / F = 2 and 2A + 3d-f is not equal to 0, what is the value of 2A / 3c-e / 2B + 3d-f

If a / b = C / D = E / F = 2 and 2A + 3d-f is not equal to 0, what is the value of 2A / 3c-e / 2B + 3d-f

a/b=c/d=e/f=2.
Suppose a = 2, then B = 1
If C = 4, then d = 2
If e = 6, then f = 3
2A + 3d-f = 2 * 2 + 3 * 2-6 = 4 is not 0
So 2A / 3c-e / 2B + 3d-f = 2 * 2 / 3 * 4-6 / 2 * 1 + 3 * 2-3 = 1 / 3-3 + 6-3 = 1 / 3
The answer is one third