The first reduction is in evaluation. (x ＾ 2 + 2x x-2-x ＾ 2 + 4x + 4x + 4x-1) divided by X + 2X-4. Where x ＾ 2 + 2x Predigestion is in evaluation. (x ＾ 2 + 2x x-2-x ＾ 2 + 4x + 4x + 4x-1) divided by X + 2X-4, where x ＾ 2 + 2x-1 = 0

The first reduction is in evaluation. (x ＾ 2 + 2x x-2-x ＾ 2 + 4x + 4x + 4x-1) divided by X + 2X-4. Where x ＾ 2 + 2x Predigestion is in evaluation. (x ＾ 2 + 2x x-2-x ＾ 2 + 4x + 4x + 4x-1) divided by X + 2X-4, where x ＾ 2 + 2x-1 = 0

The original formula = {[(X-2) / (X & # 178; + 2x)] - [(x-1) / (X & # 178; + 4x + 4)]} △ [(x-4) / (x + 2)]
={(x-2)/[x(x+2)]-[(x-1)/(x+2)²]}×[(x+2)/(x-4)]
=(x-2)/[x(x+2)]×[(x+2)/(x-4)]-[(x-1)/(x+2)²]×[(x+2)/(x-4)]
=(x-2)/[x(x-4)]-(x-1)/[(x+2)(x-4)]
=[(x-2)(x+2)]/[x(x+2)(x-4)]-[x(x-1)]/[x(x+2)(x-4)]
=[(x-2)(x+2)-x(x-1)]/[x(x+2)(x-4)]
=(x²-4-x²+x)/[x(x+2)(x-4)]
=(x-4)/[x(x+2)(x-4)]
=1/[x(x+2)
=1/(x²+2x)
Because X & # 178; + 2x-1 = 0
So x & # 178; + 2x = 1
therefore
Original formula = 1 / 1 = 1