What is the value range of the independent variable x in the function y = x + 1 / x + 3
Because the denominator is not equal to 0
So x + 3 ≠ 0
x≠-3
x∈(-∞,-3)∪(-3,+∞)
RELATED INFORMATIONS
- 1. The value range of the independent variable X of the function y = x-3 is
- 2. In the function y = x + 1 / 1, the value range of the independent variable is_______
- 3. Function y = x + 2 / 1, the value range of independent variable x
- 4. In the function y = X-2 √ 4-x, the value range of independent variable x is ()
- 5. In the function y = x to the power of 0 + √ x, the value range of the independent variable x is ()
- 6. When the independent variable of a quadratic function is 0, the function value is 1, and when the independent variable is equal to - 1 and 2, the function value is 0, then the analytic expression of the quadratic function is
- 7. Given that the absolute value of XY-2 and the absolute value of Y-1 are opposite to each other, try to find the value of the algebraic formula
- 8. It is known that / XY - 2 / (this is the sign of absolute value) and / Y - 1 / are opposite numbers (1) Find the value of X and y; (2) Find 1 / (this is the fractional sign) XY + 1 / (x + 1) (y + 1) + 1 / (x + 2) (y + 2) +... + 1 / (x + 2009) (y + 2009)
- 9. It is known that the absolute value of XY-2 is opposite to that of Y-1 Try to find the value of 1 + (x + 1) (y + 1) of XY + (x + 2) (y + 2) of XY +... + (x + 2014) (y + 2014) of XY
- 10. Solve the linear equation 4x-3z = 17, 3x + Y5z = 18, x + 2Y + Z = 2
- 11. Function y = 1 x - 2, the value range of independent variable x is______ .
- 12. When the function y = x + 1 / 1, the value range of the independent variable?
- 13. If A2 − 2A + 1 = 1-A, then the value range of a is______ .
- 14. If A-1 has square root, then the value range of a is
- 15. If the square root of a > A, then the value range of a is?
- 16. If m-2 has no square root, then the range of M is
- 17. First simplify, and then substitute x with your favorite number to evaluate: X * x-4, X * x-4x + 4, X / X-2
- 18. Simplify: (X & sup2; - 4x + 4 / 4 x & sup2; - X-2 / 2) / X-2 / 2, then choose any number you like to substitute into the evaluation!
- 19. First simplify, then evaluate: [(X-Y) 2 + (X-Y) (x + y)] x, where x = - 1, y = 12
- 20. Simplified evaluation: X (x + 2) - (x + 1) (x-1), where x = negative half 4x (Y-X) + (2x + y) (2x-y), where x = half, y = - 2