Y '' - (TaNx) y '+ 2Y = 0 Without the first question, there is a special solution y = sin X. | Math enthusiast | Mathematical art

Y '' - (TaNx) y '+ 2Y = 0 Without the first question, there is a special solution y = sin X.

Let y = C (x) SiNx, replace the original equation to get C (x), if I am not wrong, I should get it, but it is very complicated

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