Function y = - x2-2ax (0
y=-x2-2ax(0
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- 1. What is the domain of 1-e ^ x under the function f (x) = 1 / radical
- 2. What is the domain of (1-e ^ x) under the function f (x) = 1 / radical
- 3. The function f (x) = alnx-bx ^ 2 (x ≥ 0) when B = 0, if the inequality f (x) ≥ m + X holds for all a ∈ [0,3 / 2], X ∈ (1, e ^ 2), find the range of M
- 4. Let f (x) = alnx − 12x2 + BX. (1) when a = 3, B = 12, find the maximum value of F (x); (2) find the solution set of the inequality f '(x) > F (1)
- 5. Let f (x) = alnx-1 / 2x ^ 2 + BX find the solution set of the inequality f (x) > F (1)
- 6. If f (x) = AX2 + BX, and 1 ≤ f (1) ≤ 2,2 ≤ f (1) ≤ 4, find the range of F (2)
- 7. If f (x) = AX2 + BX (a ≠ 0) satisfies 1 ≤ f (- 1) ≤ 2, 2 ≤ f (1) ≤ 5, then the value range of F (- 3) is______ .
- 8. It is known that the derivative f '(x) ≤ f (x) B of quadratic function f (x) = AX2 + BX + C belongs to R. it is proved that f (x) is less than or equal to (x + C) ^ 2 when x ≥ 0
- 9. 7. Given the quadratic function f (x) = AX2 + BX + C, G (x) = λ ax + B (λ≥ 1), when | x | ≤ 1, | f (x) | ≤ 1. (1) it is proved that | a | ≤ 2 (2) Let f (0), f (1), f (- 1) denote g (1), G (- 1) (3) When | x | ≤ 1, it is proved that | g (x) | ≤ 2 λ
- 10. Given the quadratic function f (x) = AX2 + BX + C (C ≠ 0) (1) if A.B.C and f (1) = 0, it is proved that the image of F (x) has two intersections with the X axis; (2) if Changshu x1 If x 2 ∈ R, and x 1, x 2, f (x 1) ≠ f (x 2), we prove that the equation f (x) = 1 / 2 [f (x 1) + F (x 2)] must have a root belonging to (x 1, x 2)
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