1. Positive scale function y = - x, there is a point a on the image, the abscissa of point a is 2, AB is perpendicular to X axis through a, and the perpendicular foot is B, then s triangle ABO is equal to? 2. There is a point a on the image with positive scale function y = KX, the abscissa of point a is 2, AB is perpendicular to X axis through a, the perpendicular foot is B, and the s triangle ABO = 1, then K is equal to?

1. Positive scale function y = - x, there is a point a on the image, the abscissa of point a is 2, AB is perpendicular to X axis through a, and the perpendicular foot is B, then s triangle ABO is equal to? 2. There is a point a on the image with positive scale function y = KX, the abscissa of point a is 2, AB is perpendicular to X axis through a, the perpendicular foot is B, and the s triangle ABO = 1, then K is equal to?

1. A is on y = - x, the abscissa x = 2, so the ordinate y = - 2. Then drawing knows the coordinates of point a (2, - 2), point B (2,0), and point O (0,0), so the area of right triangle s = 2 * 2 / 2 = 2
2. A is on y = KX, the abscissa x = 2, so the ordinate y = 2K. Drawing knows that the abscissa of point B is also 2, so the coordinates of point a (2,2k), point B (2,0), point C (0,0), and the area of right triangle s = 2 * | 2K | / 2 = | 2K | = 1
So | K | = 1 / 2, k = 1 / 2 or K = - 1 / 2