The tangent equation of curve y = Xe ^ x + 2x + 1 at point (0,1) is
y'=e^x+xe^x+2
y'(0)=1+0+2=3
The tangent slope is 3
The tangent point is (0,1)
y-1=3x
y=3x+1
RELATED INFORMATIONS
- 1. Find the tangent equation of the curve y = 4x-x ^ 2 at point B (1,3)
- 2. In the tangent of the curve y = X3 + X-2, the tangent equation parallel to the straight line 4x-y = 1 is () A. 4x-y = 0b. 4x-y-4 = 0C. 2x-y-2 = 0d. 4x-y = 0 or 4x-y-4 = 0
- 3. A tangent equation of the curve y = x ^ 2 is 4x-y-4 = 0, and the tangent coordinates are obtained
- 4. The tangent equation of the curve y = X3 + X parallel to the straight line y = 4x-1 is () A. 4x-y = 0b. 4x-y + 2 = 0 or 4x-y-2 = 0C. 4x-y-2 = 0d. 4x-y = 0 or 4x-y-4 = 0
- 5. The tangent equation of the curve y = X3 + X-2 parallel to the straight line y = 4x-1 is () A. 4x-y = 0b. 4x-y-4 = 0C. 4x-y-2 = 0d. 4x-y = 0 or 4x-y-4 = 0
- 6. If a tangent of the curve f (x) = x ^ 2 - 1 is parallel to the straight line y = 4x - 3, the tangent equation is obtained
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- 12. The tangent equation of the curve y = xex at x = 1 is___ .
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