Given that f (x) = 1 / root x 2 + ax + A-1 is defined as (- ∞, 1-A) ∪ (- 1, + ∞), the value range of a is obtained

Given that f (x) = 1 / root x 2 + ax + A-1 is defined as (- ∞, 1-A) ∪ (- 1, + ∞), the value range of a is obtained

Because f (x) = 1 / radical x2 + ax + A-1,
So x2 + ax + A-1 > 0,
The factorization is: (x + 1) [x + (A-1)] > 0,
The corresponding equations are: - 1 and 1-A
The domain of function definition is (- ∞, 1-A) ∪ (- 1, + ∞)
Then 1-A = 2

Elden Ring Premiere

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