If f (x) is an odd function defined on R with a period of 3 and f (2) = 0, then how many real solutions does the equation f (x) = 0 have in the interval (0,6)
Four. It's been a long time
f(2)=0.
And f (x) = f (- x)
F (2 + 3K) = 0, K is any integer
Moreover, | 2 + 3K | is in the interval (0,6)
So, k = - 2, - 1,0,1
There are four solutions
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