If x, m ∈ R, try to compare the size of X Λ 2-m + 1 and 2mx-2m Λ 2 Urgent need
(x² - m + 1) - (2mx - 2m²)
= x² -2mx + 2m² - m + 1
= (x² -2mx + m²) + (m² - m + 1)
= (x - m)² + (m - 1/2)² + 3/4
Because (x - M) 178; ≥ 0, (M - 1 / 2) 178; ≥ 0
So (x - M) 178; + (M - 1 / 2) 178; + 3 / 4 > 0
So x & # 178; - M + 1 > 2mx - 2m & # 178;
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