If y = the square of root sign - (x + 1) x + the square of root sign x + 2x + 1, find the value of XY

If y = the square of root sign - (x + 1) x + the square of root sign x + 2x + 1, find the value of XY

Root and square are opposite operations, so the original formula is equal to
Y=-(x+1)x+x+2x+1
Y=-x^2-x+x+2x+1
Y=-x^2+2x+1