If x + 4y-3z = 0; 4x-5y + 2Z = 0, then 2x-y + 3Z =?

x+4y-3z=0 （1）
4x-5y+2z=0 （2）
(1) 5 + (2) × 4
21x-7z=0
∴z=3x
Substituting z = 3x into (1) yields
x+4y-9x=0
∴y=2x
Substituting y = 2x, z = 3x
2x-y + 3Z of 3y-5z
Original formula = (6x-15x) / (2x-2x + 9x)
=-9x/9x
=-1

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