When the area of triangle CPQ is the largest, the equation of line L is--

Let ∠ PCQ = a, then scpq = 1 / 2 * | CP | * | CQ | * Sina = 2sina, so if the triangle CPQ area is the largest, there must be a = 90 °, then the distance from C to the straight line is equal to R / √ 2. Let the linear L equation be a (x-1) + by = 0, then the distance from C to the straight line is d = | 2A + 4B | / √ (a ^ 2 + B ^ 2) = 2 / √ 2

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