Given (X-2) + √ Y-X + 1 = 0, find the square root of X + y
(X-2) ^ 2 is greater than or equal to 0, and the root sign Y-X + 1 is also greater than or equal to zero. The sum of two polynomials is 0, so the two polynomials are equal to 0, so x = 2, y = 1, so the square root of X + y is root sign 3
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