What number can be used for root operation?

Non negative numbers (positive and 0) can be used for square root operation

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1. Which is the function to solve the positive definite equation of coefficient matrix with square root and improved square root in MATLAB?
2. Second order unit matrix square root algorithm Find a second order matrix X, so that its square is equal to the second order identity matrix, please give the algorithm Note: this problem is a numerical method problem, only need algorithm ideas, do not need code, Another problem is as follows: A and B are known matrices of NxN respectively, and finding the unknown matrix of NxN such that axa-xb = I (identity matrix) is also a numerical algorithm The two questions are very similar. They are well done, It's the best way to solve the problem in MATLAB,
3. The arithmetic square root of 22 / 3 and 49
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7. Does any number have a square root?
8. It is known that the square root of a positive number is 2a, 3 and 1-A
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13. If the fractional equation 3x / X-2 + 5 = 8m / X-2 has an increasing root, then M =?
14. When m is the value, the fractional equation 1 / X-1 + m / X-2 = 2m + 2 / x ^ 2-3x + 2 has an increasing root
15. If the fractional equation 3xx − 1 = MX − 1 has an increasing root, then the value of M is () A. 1B. -1C. 3D. -3
16. If x > 1 / 2 (x-3), 2x + 3
17. The fractional equation: 1 / (2x + 1) = 1 / (x + n) has increasing roots, then n =? If the problem, detailed problem-solving process, thank you
18. If the fractional equation (x-a) / (x-1) - 3 / x = 1 about X has no solution, then a =? Do I have the right solution? Here's my solution: if (a + 2) x = 3, then a = 2 has no solution, When x = 0, there is no solution When x = 1, a + 2 = 3, then a = 1 ∴ a=-2 ,1
19. The fractional equation 3 / X-1 / (x + 1) + (x + a) / X (x + 1) = 0 has no solution Come on, now
20. If the fractional equation (x-a) / (x-1) - 3 / x = 1 has no solution, then a= Double x (x-1) x(x-a)-3(x-1)=x(x-1) x²-ax-3x+3=x²-x (a+2)x=3 If a = - 2 Then a + 2 = 0 Then 0 = 3, not true, If a ≠ - 2 Then x = 3 / (a + 2), if there is no solution, then this is an increasing root That is, the common denominator is 0 x(x-1)=0 x=0,x=1 3 / (a + 2) = 0 doesn't hold. Why can't x = 0 be brought into the fractional equation? Then a is an arbitrary value!