9999×7778+3333×6666.
9999×7778+3333×6666,=9999×7778+3333×3×2222,═9999×7778+9999×2222,=9999×(7778+2222),=9999×10000,=99990000;
RELATED INFORMATIONS
- 1. When an integer is multiplied by 13, the last three digits of the product are 123. What is the minimum number of such an integer?
- 2. When an integer is multiplied by 13, the last three digits of the product are 123. What is the minimum number of such an integer?
- 3. After a three digit number is multiplied by 13, the last three digits of the product are 123. Find this number
- 4. If the product of a number multiplied by 13 is an integer and the last three digits are 123, then the smallest number in such a certificate is many By the way, another 30 points
- 5. When an integer is multiplied by 13, the last three digits of the product are 123. What is the minimum number of such an integer?
- 6. 123 is both prime and odd Urgent
- 7. Use 123 numbers to form a prime number with three digits
- 8. 123*234*345*456=
- 9. 123+234+345+456+567+678
- 10. The least common multiple of 69 and 46
- 11. 999 * 2224 + 6666 * 16642012 * 2012-2010 * 20111999 + 199.9 + 19.99 + 1.999 how to calculate easily? 999 * 2224 + 6666 * 16642012 * 2012-2010 * 20111999 + 199.9 + 19.99 + 1.999 how to calculate easily?
- 12. Simple calculation: 999.9 * 0.28-0.666 * 370 The answer is 33.552
- 13. 999.9 * 0.28-6666 * 0.37 simple calculation
- 14. A simple algorithm of 234 + 98
- 15. A simple algorithm of 234 * 56 + 45 * 234-234
- 16. 234 * 36 + 63 * 234 + 234 simple algorithm
- 17. Excuse me, is there a simple calculation for 69 + 200 △ 25 × 13?
- 18. 963 × 123-321 × 69
- 19. 123123… What is the remainder of 123 divided by 99?
- 20. The sum of 123 + 2 times 123 + 3 times 123 +. + 123 times 123 divided by 7 is the remainder