Y = Y1 + Y2, where Y1 is inversely proportional to 3x, Y2 is positively proportional to - x, and when x = 1, y = - 5 / 3, when x = 2, y = 2 / 3 seek (1) The function analytic expression of Y and X (2) When x = - 1, the value of Y

Y = Y1 + Y2, where Y1 is inversely proportional to 3x, Y2 is positively proportional to - x, and when x = 1, y = - 5 / 3, when x = 2, y = 2 / 3 seek (1) The function analytic expression of Y and X (2) When x = - 1, the value of Y

y1=a/(3x);y2=-bx
The equation is as follows
a/3-b=-5/3
a/6-2b=2/3
The solution is: a = - 8; b = - 1
1) The analytic expression of Y and X is y = (3x ^ 2-8) / (3x), X is not equal to 0
2) When x = - 1, the value of Y is 5 / 3