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Given two reciprocal numbers of the equation x & # 178; - 3x-a + 1, find the value of a and its two
A:
Two reciprocal numbers of X & # 178; - 3x-a + 1 = 0
According to Weida's theorem:
x1*x2=1-a=1
The solution is a = 0
So: the equation is x ^ 2-3x + 1 = 0
The solution is: x = (3 ± √ 5) / 2
To sum up, a = 0, two are X1 = (3 + √ 5) / 2, X2 = (3 - √ 5) / 2
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