If the equation x □ - 2 (A-1) x - (B + 2) □ = 0 has two equal real roots, then the square of ab It's Square

If the equation x □ - 2 (A-1) x - (B + 2) □ = 0 has two equal real roots, then the square of ab It's Square

[2(a-1)]□-4*[-(b+2)□]=0
Namely
(a-1)□-(b+2)□=0
(a-1+b+2)(a-1-b-2)=0
(a+b+1)(a-b-3)=0