Given that the line segment AB = 1.8, the point C is on the extension line of AB, and AC = 5 / 3 BC, the length of the line segment BC is calculated

AC=5/3BC
That is 5BC = 3aC
Because BC = ac-ab
So 5 (ac-ab) = 3aC
5AC-5AB=3AC
AC = 5ab / 2 = 4.5
BC=AC-AB=4.5-1.8=2.7

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