If the line segment AB is known, extend the line segment AB to C so that BC = half AB, and extend the line segment AB to C in reverse so that ad = three-thirds AB, then the midpoint of the line segment CD is a point_

If the line segment AB is known, extend the line segment AB to C so that BC = half AB, and extend the line segment AB to C in reverse so that ad = three-thirds AB, then the midpoint of the line segment CD is a point_

As shown in the figure: we can see AB as X, then BC = 0.5x, ad = 1.5x, then DC = x + 0.5x + 1.5x = the midpoint of 3xcd: known: CD = 3x, then the midpoint is 1.5x away from C or D, just as the title goes: & nbsp; ad = 1.5x and C is away from a: CB + Ba = 0.5x + x = 1.5x, so a is the midpoint of line CD