Math problem: there are three points a, B and C on a straight line in order, ab = 50cm, BC = 20cm, point P is the midpoint of the line AC, find the length of the line BP
BP=AB-AP=AB-(AB+BC)/2=50-(50+20)/2=15
RELATED INFORMATIONS
- 1. Roll three regular hexahedral dice marked with 1, 2, 3, 4, 5 and 6 at the same time, and the numbers are a, B and C respectively. Then the probability that a, B and C are exactly the three sides of a right triangle is () A. 1216B. 172C. 136D. 112
- 2. First simplify and then evaluate the square of - AB + 6 (6 / 1ab-a) - 3a, where a is the negative square root of 9
- 3. If x1, X2 are two real roots of the equation X2 (2k + 1) x + K + 1 = 0, and x1, X2 are greater than 0 If x 1 / x 2 = 1 / 2, find the value of K How to use the condition X1 / x2 = 1 / 2?
- 4. Solve the equation 6 times 9-2 / 1X = 5 / 24 7x + 6x = 310.7x-5 = 3 / 5 X170 times 100% = 85%
- 5. 7 / 8x + 6 - (1-25%) x = 18 help me solve the equation How many steps can you take,
- 6. There are four numbers. The first three numbers form an equal ratio sequence, and the last three numbers form an equal difference sequence. The sum of the first and last two numbers is 21, and the sum of the middle two numbers is 18 ..
- 7. As shown in the figure, D is the midpoint of AB, e is the midpoint of BC, be = 1 / 5, AC = 2cm, find the length of line De ·————·————·——·——· `A`````````D`````````B`````E````C
- 8. Roll a uniform regular hexahedron dice with 1, 2, 3, 4, 5 and 6 on each side. The probability of "5" or "6" is equal to () A. 13B. 14C. 15D. 16
- 9. Given (A-7) square = 121, (B + 1) cube = - 0.064, find the square root of a + 10B
- 10. If X1 and X2 are the two real roots of the equation x ^ 2 - (2k + 1) x + K ^ 2 + 1 = 0, and X1 and X2 are greater than 1. If X1 / x2 = 0.5, find K
- 11. As shown in the figure, ab = 12cm, point C is the midpoint of AB, and point D is the midpoint of line CB
- 12. As shown in the figure, if point C is the midpoint of line AB, e and F are the midpoint of AC and BC respectively, ab = 12cm, find the length of EF Variant 1: if C is any point on the line AB, e and F are the midpoint of AC and BC respectively, ab = 12cm, then EF = -. Variant 2: if C is an extension point on the line AB, e and F are the midpoint of AC and BC respectively, ab = 12cm, then EF = -. Variant 3: if C is a reverse extension point on the line AB, e and F are the midpoint of AC and BC respectively, ab = 12cm, then EF = -. Variant 4: if C is any point on the line AB, e and F are AC respectively, If the midpoint of BC, ab = 12cm, then EF = - (draw the figure according to the situation and write out the complete process
- 13. It is known that the line segment AB is 10cm. Point C is any point on the line segment AB, and Mn is AC.BC Midpoint, find the length of Mn
- 14. Given that the line segment AB = 10cm, point C is any point on the line segment AB, m and N are the midpoint of AC and BC respectively, the length of Mn can be obtained
- 15. Given the line AB = 10cm, C is any point on the line AB, M is the midpoint of AC, n is the midpoint of BC, find the length of Mn! There are three points a, B and C on the straight line L. we know that BC = 2Ab, D is the midpoint of AC, and BD = 12cm?
- 16. As shown in the figure, ab = 12cm, point C is on the line AB, and AC = 10cm, m and N are the midpoint of AC and BC respectively
- 17. As shown in the figure, C is any point on AB, M is the midpoint of AC, and N is the midpoint of BC. If AB = 10cm, calculate the Mn degree of the line segment
- 18. C is any point on the line AB, M is the midpoint of AC, and N is the midpoint of ab. if BC = 10cm, then the length of the line Mn is A M C N B _________________________ infer
- 19. As shown in the figure, points a, B and C are successively on line L, point m is the midpoint of line AC, and point n is the midpoint of line BC. If AB = 12, the length of Mn is () A. 6B. 4C. 5D. 2
- 20. It is known that the line segment AB = CD, which coincides with one third of each other, m and N are the midpoint of AB and CD respectively, and Mn = 14cm, the length of AD