If the integers a, B, C and D satisfy ABCD = 25 and a > b > C > D, then | a + B | + | C + D | equals () A. OB. 10C. 2D. 12
25 = 5 × 5 × 1 × 1 = 5 × (- 5) × 1 × (- 1), then a = 5, B = 1, C = - 1, d = - 5, | a + B | + | C + D | = | 5 + 1 | + | - 1-5 | = 6 + 6 = 12
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