In △ ABC, ab = AC, the perpendicular of AB intersects AC at F. if AB = 12cm and the perimeter of △ BCF is 20cm, then the perimeter of △ ABC is (process)

From the intersection AC of the middle perpendicular of AB side with F, AF = BF, so the perimeter of △ BCF = AC + AB = 20 and ab = 12cm
So the perimeter of △ ABC = 20 + 12 = 32cm
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