Solution equation (X &; 0 &; 5 + x) (X &; 0 &; 5 + x-14) + 24 = 0

(x²+x)(x²+x-14)+24=0
(x²+x)²-14(x²+x)+24=0
(x²+x-2)(x²+x-12)=0
(x-1)(x+2)(x-3)(x+4)=0
So x = 1 or x = - 2 or x = 3 or x = - 4
If you don't understand, I wish you a happy study!

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