It is known that the area of triangle ABC is the fourth power of 6m and the third power of the square of 3A. If the height of one side is the square of 3M, what is the length of this side? RT

Triangle area = 1 / 2 bottom × height,
Bottom = 2 × area △ height
=2(6m^4-3am^3)÷(3m^2)
=2(2m^2-am)
=4m^2-2am

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