The square roots of a positive number are 3x-5 and 8-6x. Find the value of X

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• 2. 18x-66=7x Is an equation. Find the formula
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• 7. 2、 In the class committee election of a class, it is known that Kan Zhiqiang, Shang Lili and Wang Honghong are candidates for the class committee (1) If Kan Zhiqiang is elected, Wang Honghong will also be elected; (2) If Shang Lili is elected, Wang Honghong will not be elected; (3) If Wang Honghong is not elected, Kan Zhiqiang or Shang Lili can be elected Try to use the main disjunctive paradigm to find all the possibilities of three elected class committee be deeply grateful!
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• 13. Example: R is a reflexive relation on the set X. it is proved that R is symmetric and transitive if and only if There is a difference between a, b > and in R Example: let R 1 and R 2 be two equivalence relations in set a, and R 1, R 2 = R 2, R 1, R 2 is also the equivalence relation on a Proof: 1) reflexivity (omitted) 2) Symmetry (omitted) 3) Transitivity: If, then And, so, so And then by and by transmission, we get, Again by knowing, so, so, again by and is transmitted, get, and so Example: let R be a reflexive transitive binary relation on set a, and let t also be a binary relation on set a, and satisfy the following conditions: . prove: t is the equivalent relation on a
• 14. After the elementary transformation of matrix, is the original matrix equal to the transformed matrix? Why are they equal? Take R1 * 999 1 0 0 0 0 5 2 8 0 2 3 4 So a11 is 999,
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• 17. Why is the matrix representing the transformation always placed on the left side of the transformed matrix in matrix multiplication
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• 19. Discrete mathematics problem, let R be a binary relation on a, define s = {(a, b) | &; C ∈ a, (a, c) ∈ R, (C, b) ∈ r}, prove Let R be a binary relation on a, define s = {(a, b) | &; C ∈ a, (a, c) ∈ R, (C, b) ∈ r}, prove that if R is an equivalence relation on a, then s is also an equivalence relation, and S = R It's OK to connect~
• 20. How is the binary relation calculated? R1={(a,b),(c,d)},R2={(b,c),(d,e)} So R1 * R2 = {(a, c)}, R2 * R1 = {(B, d)} What do I think, R1 * R2 = {(a, c), (C, e)}, Because (a, b) (B, c) can get (a, c) (C, d) (D, e) can get (C, e)