In the natural number within 10, find out three different prime numbers to form a three digit number, so that the number is a multiple of 2 and 3 at the same time. The number may be ()

Prime numbers within 10 are 2, 3, 5, 7
If it is divisible by 2, the last mantissa must be divisible by 2
So a bit is two
The number is XX2
And because this number can be divided by 3, so the sum of each number is a multiple of 3
Obviously, 2 + 3 + 7 = 12, divisible by 3
So the number of components might be 372 732

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