Given - x + 2Y = 5, then the value of 5 (x-2y) ∧ 2-3 (x-2y) - 60 is () a Given - x + 2Y = 5, then the value of 5 (x-2y) ∧ 2-3 (x-2y) - 60 is () A-17 B-7 C-3 d 7

RELATED INFORMATIONS

• 1. Expand the function f (x) = cosx into a power series of X. thank you
• 2. Finding the (x + π / 3) power series of function cosx
• 3. A = [cosx - SiNx; SiNx cosx], find the nth power of A
• 4. How LNX develops into power series
• 5. Finding Taylor series of F (x) = LNX at x = 2 How to find the convergence domain How to calculate the open and closed interval of convergence domain
• 6. Why is the commonly used Taylor series ln (1 + x) instead of LNX? It is the alpha power of (1 + x), not the alpha power of X
• 7. The function f (x) = LNX is expanded by Taylor series when x = 1
• 8. F (x) = (1 + X Λ 2) e Λ x is expanded into a power series of X
• 9. The expansion of F (x) = 1 / (2 + x) into a power series of X It also points out the establishment range
• 10. It is known that log189 = a, 18b = 5, and log3645 is represented by a and B
• 11. Given - x + 2Y = 5, then the value of 5 (x-2y) * 2-3 (x-2y) - 60 is_
• 12. If x-2y = 5, then the value of 5 (2y-x) ^ 2-3 (2y-x) - 60 is
• 13. When 2y-x = 5, (x-2y) & sup2; - 3 (- x + 2Y) + 60
• 14. Given - x + 2Y = 5, then the value of 5 (x-2y) 2-3 (x-2y) - 60 is______ ．
• 15. When 2y-x = 5, 5 (x-2y) 2-3 (- x + 2Y) - 60=______ ．
• 16. Given - x + 2Y = 5, then the value of 5 (x-2y & # 178;) - 3 (x-2y) - 60
• 17. If the absolute value of (X-5) ² + 2Y + 1 = 0, then x-2y=
• 18. Let X of G (x) = e, X ≤ 0 LNX, x > 0, then G (g (1 / 2)) is equal to?
• 19. It is known that f (x) = ax LNX, X belongs to (0, e], G (x) = LNX / x, where e is a natural number and a belongs to R (1) The monotonicity and extremum of a = 1, f (x) are discussed (2) Verification: under the condition of (1), f (x) > G (x) + 1 / 2 (3) If there is a real number a, the minimum value of F (x) is 3. If there is, the value of a can be obtained. If not, the reason is given
• 20. If G (x) = e ^ x, X ≤ 0 = LNX, x > 0, then G (g (1 / 2))=