Under the simplified radical [1-cos (a-pi)] 2 -3pi

Should it be under the root sign {[1-cos (a-pi)] 2}?
[1-cos(a-pi)]\2
=[1-cos(pi-a)]/2
=[1+cosa]/2
=[1+2(cos(a/2))^2-1]/2
=(cos(a/2))^2
And - 3pi / 2

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