a+b+c=0 a-b+c=6 4a+2b+c=3 To solve the linear equation of three variables a + B + C = 0, 4A + 2B + C = 3, A-B + C = 6

a+b+c=0 ①
4a+2b+c=3 ②
a-b+c=6 ③
① - 3
2b=-6；b=-3
② - 1
3A + B = 3, B = - 3
3a+(-3)=3,a=2
When a = 2 and B = - 3 are substituted into (1), the following results are obtained
2-(-3)+c=6
c=1
The solution of the equation is: a = 2, B = - 3, C = 1

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