The three sides a, B, C of the unequal triangle ABC are integers and a & sup2; + B & sup2; - 4B + 13 = 0

The three sides a, B, C of the unequal triangle ABC are integers and a & sup2; + B & sup2; - 4B + 13 = 0

a²+b²-4b+13=0.
That is, a & # 178; + B & # 178; - 4B + 4 + 9 = 0
a²+(b-2)²+9=0.
It's impossible