The absolute value of the difference between the a power of 2 and the B power of 3-11 + (the B power of 4 × 3-The C power of 3x5-1) square = 0, find out what a B C is Add 6x2 to the power of a - 4x3 to the power of B + 1. The absolute value of the sum is 0. Please give me the answer by tomorrow

The absolute value of the difference between the a power of 2 and the B power of 3-11 + (the B power of 4 × 3-The C power of 3x5-1) square = 0, find out what a B C is Add 6x2 to the power of a - 4x3 to the power of B + 1. The absolute value of the sum is 0. Please give me the answer by tomorrow

Are you from high school? You should have learned logarithm? Because the range of three polynomials is [0, + ∞), and their sum is zero, so the values of the three polynomials are respectively zero. By combining the three formulas and substituting them equally, you can calculate a = 43 / 10 logarithm with 2 as the base, B = 67 / 10 logarithm with 3 as the base, and then you can calculate the value of C by substituting the value of B into the second formula, You can do it yourself^_ ^Give it a try^_^