There are five cards whose numbers are 0, 4, 5, 6 and 7 respectively. Three of them form a three digit number, among which () are multiples of 4 A. 12B. 13C. 14D. 15

There are five cards whose numbers are 0, 4, 5, 6 and 7 respectively. Three of them form a three digit number, among which () are multiples of 4 A. 12B. 13C. 14D. 15

If the last two digits can be divided by 4, then the last two digits can be divided by 4 (because all multiples of 100 can be divided by 4). In this way, the last two digits can only be 04, 40, 56, 60, 64, 76. When the last two digits are 04, choose one from 5, 6, 7, three from 100; when the last two digits are 40, choose one from 5, 6, 7