Given that the real number a satisfies [2006-a] + √ (A-2007) = a, what is the square of a-2006 [denotes absolute value

Because the root sign must be greater than or equal to 0, so: A-2007 > = 0
That is: a > = 2007
Simplification:
A-2006 + root (A-2007) = a
Root (A-2007) = 2006
a-2007=2006^2
a-2006^2=2007

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