Sum of the first n terms of sequence: SN = 3an-3 ^ (n + 1) (1) prove that (a (n + 1) - 2 / 3an) is an equal ratio sequence (2) formula for finding an general term (3) compare Sn / 3 ^ n with 6N / (2n + 1) It's OK to ask the first question first,
sn+1=3a(n+1)-3^(n+2)
sn=3an-3^(n+1)
a(n+1)=3(an+1-an)-2*3^(n+1)
2a(n+1)=3an+2*3^(n+1)
A (n + 1) - 3 / 2An = 3 ^ (n + 1) is an equal ratio sequence
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