Try to explain: for any natural number n, the value of n (n + 5) - (n-3) (n + 2) can be divided by 6

Try to explain: for any natural number n, the value of n (n + 5) - (n-3) (n + 2) can be divided by 6

∵ n (n + 5) - (n-3) (n + 2) = (N2 + 5N) - (n2-n-6) = N2 + 5n-n2 + N + 6 = 6N + 6 = 6 (n + 1) and N ≥ 1 ∵ can always be divisible by 6