Let Sn = 2n + A and TN = n2-2n + B, then a + B=______ .
The sum of the first n terms of ∵ equal ratio sequence {an} is Sn = 2n + A, ∵ a = - 1 ∵ equal difference sequence {BN} is TN = n2-2n + B ∵ B = 0 ∵ a + B = - 1, so the answer is: - 1
RELATED INFORMATIONS
- 1. It is known that the general term formula of sequence an is an = 2N-1, and the sum of the first n terms of sequence BN is TN and satisfies TN = 1-b The general term formula of BN
- 2. Given that the general term formula of the sequence {an} is an = n / N ^ 2 + 156 (n ∈ n +), what is the maximum term of the sequence
- 3. If the general term formula of sequence {an} is an = ncosn π 2, and the sum of the first n terms is Sn, then s2012 is equal to () A. 1006B. 2012C. 503D. 0
- 4. In the known sequence {an}, an = nn2 + 156, then the largest term of the sequence {an} is the second______ Item
- 5. If the general term formula of the sequence {an} is an = n / (n ^ 2 + 156) (n ∈ n +), find the term with the largest mean value of the sequence
- 6. Given that the general term formula of the sequence {an} is an = n / N ^ 2 + 156 (n belongs to positive integer), what is the maximum term of the sequence
- 7. Given 8 ^ m = 3,4 ^ n = 6, find the value of 2 ^ 6m + 2n + 1
- 8. Given 8 ^ m = 12,4 ^ n = 6, find the value of 2 ^ (6m-2n + 1)
- 9. (1 + 2 + 3 + 4 +. 2n) / 1 + 3 + 5 + 7 +. 2N-1 = 21 / 10
- 10. Given the sequence √ 3, √ 7, √ 11, √ 15,., then 5 √ 3 is its number one?
- 11. (1) Given that the sum of the first n terms of the sequence an is Sn, satisfying Sn = an & # 178; + BN, it is proved that an is an arithmetic sequence (2) It is known that the sum of the first n terms of the arithmetic sequence an is Sn, and it is proved that Sn / N is also an arithmetic sequence
- 12. The first n terms of the sequence {an} and Sn = 2n & # 178; + n-1, then the general term formula of the sequence is? How is the process solved?
- 13. Every item of sequence an is a positive number, and Sn is the sum of its first n terms. For any n which belongs to a positive integer, there is always an, Sn, an & # 178; a general formula for finding an in arithmetic sequence Let BN = an (1 / 2) 178; the sum of the first n terms of BN is TN, and prove that 1 / 2 ≤ TN ≤ 2
- 14. Given the first n terms of the arithmetic sequence {an} and Sn = - 2n2-n, how to find the expression of the general term an? Sn-1 = - 2 (n-1) & # 178; - (n-1) are calculated?
- 15. It is known that the sum of the first n terms of a sequence is Sn = N2 + 3N, and it is proved that {an} is an arithmetic sequence. What if Sn = N2 + 3N + 1?
- 16. It is known that the sum of the first n terms of the sequence is Sn = n2-3n + 1, (1) find the general term formula, (2) try to judge whether the sequence an is an arithmetic sequence
- 17. 1. Given the first n terms of a sequence and Sn = n square + n-1, is it an arithmetic sequence?
- 18. Given the general term formula of sequence {an} an = n & # 178; + N, then the first n terms of {an} and Sn =?
- 19. Given that the sum of the first n terms of the sequence {an} is Sn = n & # 178; + n & # 189; N, find the general term formula of the sequence
- 20. Given that the sum of the first n terms of the sequence {an} is Sn = n & # 178; + N + 1, then the general term formula of {an} is?