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1+3+5+97+99/2+4+6+98+100=? 1 + 3 + 5 +... + 97 + 99 / 2 + 4 + 6 +... + 98 + 100 =? It's a mistake
Let m = 1 + 2 + 3 +... + 98 + 99 + 100, (1)
M=100+99+98+...+3+2+1（2）
(1) + 2
2M=（1+100）+（2+99++（3+98）+...（98+3）（+（99+2）+（100+1）
∴2M=101×100,
That is, M = 101 × 100 ÷ 2 = 5050, the building owner chooses me!
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