Let x-n (1.5,4) calculate P {x2.5} Let x-n (1.5,4) compute P {X & lt; = 3.5}, P {X & gt; 2.5} a problem about probability
k(2 x2_ 2/3 x3 ) k=3/8 (2) P{1<x<3}= =0.8413 P {x<=3.5} =P{x<=1}=0.8413 P{x>2.5}= =0.3085 P {X>2.5}=1-P {x<=2.5}=1-P {x<=0.5}=1-0.6915=0.3085
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