What about the limit of Ln (1 + 2x) / sin4x when x tends to zero
This is an infinitive
Do it according to the law of ruobita
lim ln(1+2x)/sin4x
=lim 2/(1+2x)/(4cos4x)
=2/4=1/2
This is an infinitive
Do it according to the law of ruobita
lim ln(1+2x)/sin4x
=lim 2/(1+2x)/(4cos4x)
=2/4=1/2